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Python Searching

From WikiOD

Remarks[edit | edit source]

All searching algorithms on iterables containing n elements have O(n) complexity. Only specialized algorithms like bisect.bisect_left() can be faster with O(log(n)) complexity.

Getting the index for strings: str.index(), str.rindex() and str.find(), str.rfind()[edit | edit source]

String also have an index method but also more advanced options and the additional str.find. For both of these there is a complementary reversed method.

astring = 'Hello on StackOverflow'
astring.index('o')  # 4
astring.rindex('o') # 20

astring.find('o')   # 4
astring.rfind('o')  # 20

The difference between index/rindex and find/rfind is what happens if the substring is not found in the string:

astring.index('q') # ValueError: substring not found
astring.find('q')  # -1

All of these methods allow a start and end index:

astring.index('o', 5)    # 6
astring.index('o', 6)    # 6 - start is inclusive
astring.index('o', 5, 7) # 6
astring.index('o', 5, 6) #  - end is not inclusive

ValueError: substring not found

astring.rindex('o', 20) # 20 
astring.rindex('o', 19) # 20 - still from left to right

astring.rindex('o', 4, 7) # 6

Searching for an element[edit | edit source]

All built-in collections in Python implement a way to check element membership using in.

List[edit | edit source]

alist = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
5 in alist   # True
10 in alist  # False

Tuple[edit | edit source]

atuple = ('0', '1', '2', '3', '4')
4 in atuple    # False
'4' in atuple  # True

String[edit | edit source]

astring = 'i am a string'
'a' in astring   # True
'am' in astring  # True
'I' in astring   # False

Set[edit | edit source]

aset = {(10, 10), (20, 20), (30, 30)}
(10, 10) in aset  # True
10 in aset        # False

Dict[edit | edit source]

dict is a bit special: the normal in only checks the keys. If you want to search in values you need to specify it. The same if you want to search for key-value pairs.

adict = {0: 'a', 1: 'b', 2: 'c', 3: 'd'}
1 in adict                 # True   - implicitly searches in keys
'a' in adict               # False
2 in adict.keys()          # True   - explicitly searches in keys
'a' in adict.values()      # True   - explicitly searches in values
(0, 'a') in adict.items()  # True   - explicitly searches key/value pairs

Getting the index list and tuples: list.index(), tuple.index()[edit | edit source]

list and tuple have an index-method to get the position of the element:

alist = [10, 16, 26, 5, 2, 19, 105, 26]
# search for 16 in the list
alist.index(16) # 1
alist[1]        # 16

alist.index(15)

ValueError: 15 is not in list

But only returns the position of the first found element:

atuple = (10, 16, 26, 5, 2, 19, 105, 26)
atuple.index(26)   # 2
atuple[2]          # 26
atuple[7]          # 26 - is also 26!

Searching key(s) for a value in dict[edit | edit source]

dict have no builtin method for searching a value or key because dictionaries are unordered. You can create a function that gets the key (or keys) for a specified value:

def getKeysForValue(dictionary, value):
    foundkeys = []
    for keys in dictionary:
        if dictionary[key] == value:
            foundkeys.append(key)
    return foundkeys

This could also be written as an equivalent list comprehension:

def getKeysForValueComp(dictionary, value): 
    return [key for key in dictionary if dictionary[key] == value]

If you only care about one found key:

def getOneKeyForValue(dictionary, value):
    return next(key for key in dictionary if dictionary[key] == value)

The first two functions will return a list of all keys that have the specified value:

adict = {'a': 10, 'b': 20, 'c': 10}
getKeysForValue(adict, 10)     # ['c', 'a'] - order is random could as well be ['a', 'c']
getKeysForValueComp(adict, 10) # ['c', 'a'] - dito
getKeysForValueComp(adict, 20) # ['b']
getKeysForValueComp(adict, 25) # []

The other one will only return one key:

getOneKeyForValue(adict, 10)   # 'c'  - depending on the circumstances this could also be 'a'
getOneKeyForValue(adict, 20)   # 'b'

and raise a StopIteration-Exception if the value is not in the dict:

getOneKeyForValue(adict, 25)

StopIteration

Getting the index for sorted sequences: bisect.bisect_left()[edit | edit source]

Sorted sequences allow the use of faster searching algorithms: bisect.bisect_left()1:

import bisect

def index_sorted(sorted_seq, value):
    """Locate the leftmost value exactly equal to x or raise a ValueError"""
    i = bisect.bisect_left(sorted_seq, value)
    if i != len(sorted_seq) and sorted_seq[i] == value:
        return i
    raise ValueError

alist = [i for i in range(1, 100000, 3)] # Sorted list from 1 to 100000 with step 3
index_sorted(alist, 97285) # 32428
index_sorted(alist, 4)     # 1
index_sorted(alist, 97286)

ValueError

For very large sorted sequences the speed gain can be quite high. In case for the first search approximatly 500 times as fast:

%timeit index_sorted(alist, 97285)
# 100000 loops, best of 3: 3 µs per loop
%timeit alist.index(97285)
# 1000 loops, best of 3: 1.58 ms per loop

While it's a bit slower if the element is one of the very first:

%timeit index_sorted(alist, 4)
# 100000 loops, best of 3: 2.98 µs per loop
%timeit alist.index(4)
# 1000000 loops, best of 3: 580 ns per loop

Searching nested sequences[edit | edit source]

Searching in nested sequences like a list of tuple requires an approach like searching the keys for values in dict but needs customized functions.

The index of the outermost sequence if the value was found in the sequence:

def outer_index(nested_sequence, value):
    return next(index for index, inner in enumerate(nested_sequence) 
                      for item in inner 
                      if item == value)

alist_of_tuples = [(4, 5, 6), (3, 1, 'a'), (7, 0, 4.3)]
outer_index(alist_of_tuples, 'a')  # 1
outer_index(alist_of_tuples, 4.3)  # 2

or the index of the outer and inner sequence:

def outer_inner_index(nested_sequence, value):
    return next((oindex, iindex) for oindex, inner in enumerate(nested_sequence) 
                                 for iindex, item in enumerate(inner) 
                                 if item == value)

outer_inner_index(alist_of_tuples, 'a') # (1, 2)
alist_of_tuples[1][2]  # 'a'

outer_inner_index(alist_of_tuples, 7)   # (2, 0)
alist_of_tuples[2][0]  # 7

In general (not always) using next and a generator expression with conditions to find the first occurrence of the searched value is the most efficient approach.

Searching in custom classes: __contains__ and __iter__[edit | edit source]

To allow the use of in for custom classes the class must either provide the magic method __contains__ or, failing that, an __iter__-method.

Suppose you have a class containing a list of lists:

class ListList:
    def __init__(self, value):
        self.value = value
        # Create a set of all values for fast access
        self.setofvalues = set(item for sublist in self.value for item in sublist)

    def __iter__(self):
        print('Using __iter__.')
        # A generator over all sublist elements
        return (item for sublist in self.value for item in sublist)

    def __contains__(self, value):
        print('Using __contains__.')
        # Just lookup if the value is in the set
        return value in self.setofvalues

        # Even without the set you could use the iter method for the contains-check:
        # return any(item == value for item in iter(self))

Using membership testing is possible using in:

a = ListList([[1,1,1],[0,1,1],[1,5,1]])
10 in a    # False
# Prints: Using __contains__.
5 in a     # True
# Prints: Using __contains__.

even after deleting the __contains__ method:

del ListList.__contains__
5 in a     # True
# Prints: Using __iter__.

Note: The looping in (as in for i in a) will always use __iter__ even if the class implements a __contains__ method.

Credit:Stack_Overflow_Documentation